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2 1/4 4 1/8 8 1/16 16 1/32 32 1/64........up to infinity
S=21/422/823/1624/32....S=21/4+2/8+3/16....S=21/4(1+2/2+3/4+4/8....)S=21/4(t)t=1+2/2+3/4+4/8.... (infinite AGP with a=1,r=1/2,d=1)t=a/(1-r) + dr/(1-r)2t=2+2=4S=2
Dear Student,Please find below the solution to your problem.S = 2^(1/4) * 2^(2/8) * 2^(3/16) * 2^(4/32)....S = 2^(1/4 + 2/8 + 3/16....)S = 2^1/4(1+2/2+3/4+4/8....)S = 2^1/4(t)t = 1 + 2/2 + ¾ + 4/8 .... (infinite AGP with a=1,r=1/2,d=1)t = a/(1-r) + dr/(1-r)2t = 2+2 = 4S = 2Thanks and Regards
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