Dear Student,
Please find below the solution to your problem.
S = 2^(1/4) * 2^(2/8) * 2^(3/16) * 2^(4/32)....
S = 2^(1/4 + 2/8 + 3/16....)
S = 2^1/4(1+2/2+3/4+4/8....)
S = 2^1/4(t)
t = 1 + 2/2 + ¾ + 4/8 .... (infinite AGP with a=1,r=1/2,d=1)
t = a/(1-r) + dr/(1-r)2
t = 2+2 = 4
S = 2
Thanks and Regards