Algebra
∑15m=1sin(2m-1) x = [sin{(x+29x)/2}* sin15x ] /sin x. How??Please show the steps.
∑15m=1sin(2m-1) x = [sin{(x+29x)/2}* sin15x ] /sin x. How??Please show the steps.
1 Answer
Deepak Kumar Shringi
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algebra
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