Grade 12th passAlgebra
1-(y-1)+(y-1)²-(y-1)³+..…-(y-1)^17. Then find coefficient of y²
1 Answer
Arun
Dear student
This is a G.P.
a = 1
r = -(y-1)
Now
Total number of terms = 18
Hence
Sum = (-1)^18 (y-1)^18 - 1/(-y +1 -1)
= (y-1)^18 - 1 /-y
Now for coefficient of y²
Numerator should be y³.
Hence coeff of y³ in numerator = 18C3 y³ (-1)^15
Hence now complete term = 18C3
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