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(1-i) 6 +(1-i) 3 =

(1-i)6 +(1-i)3=

Grade:11

1 Answers

rajat Bansal
20 Points
6 years ago
(1-i)^2=-2i
so we can write the question like this
 ( (1-i)^2 )^3+(1-i)(1-i)^2
(-2i)^3 +(1-i)(-2i)
8i-2i-2
6i-2
 

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