1. A wire of length 2 units is cut into two parts which are bent respectively to form a square of side = x units and a circle of radius = r units. If the sum of the areas of the square and the circle so formed is minimum, then:
Narendra
8 Years agoGrade 12
1 Answer
Samyak Jain
8 Years ago
A wire of length 2 units is cut into two parts which are bent respectively to form a square of side = x units and a circle of radius = r units.
Perimeter of square = 4x & perimeter of circle (i.e. its circumference) = 2r
So sum of perimeters of given figures is equal to 2,
i.e., 4x + 2r = 2 or x = (1 – r)/2
Sum of areas of the square & the circle = x2 + r2 , Put x = (1 – r)/2
= [(1 – r)/2]2 + r2
= (1 – 2r + 2 r2)/4 + r2
= (1/4)[1 – 2r + 2 r2 +4r2]
Differentiate the above expression wrt x and equate it to zero.