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```
1+4/5+7/5^2+10/5^3+......anant pado ka yog hai Sin^2(π/8+A/2) -sin^2(π/8-A/2)

```
one year ago

2068 Points
```							hello ravi, note that the given series is an infinite AGP (arithmetico geometric progression) with common diff d= 3, common ratio r= 1/5, a= 1. we can directly use the formula for the sum of an infinite AGP:S= a/(1 – r) + dr/(1 – r)^2putting the values, we haveS= 35/16now i dont understand what you mean by sin^2(π/8+A/2) -sin^2(π/8-A/2) ?? what is A here. kindly clarify.kindly approve :)
```
one year ago
Arun
25160 Points
```							Dear student In 2nd question it is formula of sin²x - sin²y = sin (x+y) sin (x-y)Hence = Sin (π/8 +A/2 + π/8 -A/2) sin (π/8 + A/2 - (π/8 -A/2)) = Sin (π/4) sin (A) = (1/√2) sinA
```
one year ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions