| 1/2(Z1 + z2) + √z1z2 | + |1/2 (Z1 + z2) - √z1z2

Question

| 1/2(Z1 + z2) + √z1z2 | + |1/2 (Z1 + z2) - √z1z2 | is equal to-(a) |Z1+z2|(b) |z1-z2|(c) |Z1| + |z2|(d) |Z1| - |z2|

Aditya Gupta · Accepted Answer

we know that |a+b|^2= |a|^2+|b|^2+2Re(abarb) = |(a+b)^2|= |a^2+b^2+2ab|and |a – b|^2= |a|^2+|b|^2 – 2Re(abarb)= |(a – b)^2|=|a^2+b^2 – 2ab|adding |a^2+b^2+2ab|+|a^2+b^2 – 2ab|= 2*[|a|^2+|b|^2]a and b being complex quantities.if we let a and b = rootz1 and rootz2, then | 1/2(Z1 + z2) + √z1z2 | + |1/2 (Z1 + z2) - √z1z2 |= ½*[2(|Z1| + |z2|)]= |z1| + |z2|

Algebra> | 1/2(Z1 + z2) + √z1z2 | + |1/2 (Z1 + z2)...

| 1/2(Z1 + z2) + √z1z2 | + |1/2 (Z1 + z2) - √z1z2 | is equal to-
(a) |Z1+z2|
(b) |z1-z2|
(c) |Z1| + |z2|
(d) |Z1| - |z2|

Paridhi sharma , 6 Years ago

Aditya Gupta

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Algebra> | 1/2(Z1 + z2) + √z1z2 | + |1/2 (Z1 + z2)...

| 1/2(Z1 + z2) + √z1z2 | + |1/2 (Z1 + z2) - √z1z2 | is equal to-(a) |Z1+z2|(b) |z1-z2|(c) |Z1| + |z2|(d) |Z1| - |z2|

Paridhi sharma , 6 Years ago

Aditya Gupta

Provide a better Answer & Earn Cool Goodies

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Ask a Doubt

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| 1/2(Z1 + z2) + √z1z2 | + |1/2 (Z1 + z2) - √z1z2 | is equal to-
(a) |Z1+z2|
(b) |z1-z2|
(c) |Z1| + |z2|
(d) |Z1| - |z2|