1) 2 to the power x=1-x² solve for x. 2)|x²+x+1|=3 where x€R ,find x

Question

1) 2 to the power x=1-x² solve for x. 2)|x²+x+1|=3 where x€R ,find x ​ ​

Arun · Answer

2)- |x 2 + x+ 1| = 3 now when we open mod, there are two cases- 1 st Case- x 2 + x+ 1 = 3 x 2 + x –2 = 0 x = – 2, x = 1 2nd Case- x 2 + x+ 1 = –3 x 2 + x+ 4 = 0 in this equation D hence roots are imaginary.

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1) 2 to the power x=1-x² solve for x. 2)|x²+x+1|=3 where x€R ,find x

1) 2 to the power x=1-x² solve for x. 2)|x²+x+1|=3 where x€R ,find x

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1) 2 to the power x=1-x² solve for x. 2)|x²+x+1|=3 where x€R ,find x ​ ​

1) 2 to the power x=1-x² solve for x. 2)|x²+x+1|=3 where x€R ,find x​​

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1) 2 to the power x=1-x² solve for x. 2)|x²+x+1|=3 where x€R ,find x

1) 2 to the power x=1-x² solve for x. 2)|x²+x+1|=3 where x€R ,find x