1!+2!+........+95! Is devide by 15 .what will be the reminder of this

When 1!+2!+3!+4!+5!....(95)! is divided by 15all the factorails from 5! + 6! + 7! + ... (95)! are divisible by 15 as they contain 3*5 as one of their factor.

Thus the remainder can be found by dividing 1!+2!+3!+4! by 15 = 33 by 15. = 3

Regards

Arun