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```
1/2 [ 2{n(n+1)/2}^2 – n(n+1)(2n+1)/6 + n(n+1)/2 ] = 1/12 [ n(n+1) {3(n^2) + n +2}] Please show how??
1/2 [ 2{n(n+1)/2}^2 –  n(n+1)(2n+1)/6  + n(n+1)/2 ] = 1/12 [ n(n+1) {3(n^2) + n +2}]Please show how??

```
2 years ago

2074 Points
```							taking n(n+1)/6 common, we get1/2 [ 2{n(n+1)/2}^2 –  n(n+1)(2n+1)/6  + n(n+1)/2]=[3n(n+1) – (2n+1)+3]*n(n+1)/12=[3n^2+3n – 2n – 1+3]*n(n+1)/12=1/12 [ n(n+1) {3(n^2) + n +2}]
```
2 years ago
Deepak Kumar Shringi
4404 Points
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2 years ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions