Water drops are falling regularly at constant interval of 1s from a tap. If total time taken by a drop to strike is 4s,then distance between 2nd and 3rd drop when 1st drop just hits the ground is?

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jitender · Answer

Time taken by 1st drop to reach groundS=ut+1/2 at^2 ( 2nd equation of motion)Now t= 4secu=0And a=g=10m/s^2S=height of tap=80mNow 2nd drop covers s2= 1/2 ×10×9=45mS3=1/2 ×10×4=20mBecause interval of dropping is 1 sec.S2-s3=45-20=25m

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Water drops are falling regularly at constant interval of 1s from a tap. If total time taken by a drop to strike is 4s,then distance between 2nd and 3rd drop when 1st drop just hits the ground is?

Water drops are falling regularly at constant interval of 1s from a tap. If total time taken by a drop to strike is 4s,then distance between 2nd and 3rd drop when 1st drop just hits the ground is?

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Water drops are falling regularly at constant interval of 1s from a tap. If total time taken by a drop to strike is 4s,then distance between 2nd and 3rd drop when 1st drop just hits the ground is?

Water drops are falling regularly at constant interval of 1s from a tap. If total time taken by a drop to strike is 4s,then distance between 2nd and 3rd drop when 1st drop just hits the ground is?

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