Water drops are falling regularly at constant interval of 1s from a tap. If total time taken by a drop to strike is 4s,then distance between 2nd and 3rd drop when 1st drop just hits the ground is?
Akshara , 8 Years ago
Grade 12th pass
1 Answers
jitender
Time taken by 1st drop to reach groundS=ut+1/2 at^2 ( 2nd equation of motion)Now t= 4secu=0And a=g=10m/s^2S=height of tap=80mNow 2nd drop covers s2= 1/2 ×10×9=45mS3=1/2 ×10×4=20mBecause interval of dropping is 1 sec.S2-s3=45-20=25m
Last Activity: 8 Years ago
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.