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TWO MASSES OF m ARE PROJECTED FROM A TALL TOWER . ONE IS VERTICALLY UPWARDS AND ONE IS VERTICALLY DOWNWARDS WITH SAME SPEED UNDER GRAVITY. IF ACCELERATION DUE TO GRAVITY IS ‘g’ THEN ACCELERATION OF THEIR CENTER OF MASS IS WHAT ?

TWO MASSES OF m ARE PROJECTED FROM A TALL TOWER . ONE IS VERTICALLY UPWARDS AND ONE IS VERTICALLY DOWNWARDS WITH SAME SPEED UNDER GRAVITY. IF ACCELERATION DUE TO GRAVITY IS ‘g’ THEN ACCELERATION OF THEIR CENTER OF MASS IS WHAT ?

Grade:12

1 Answers

Eshan
askIITians Faculty 2095 Points
4 years ago
Dear student,

Acceleration of center of mass=\dfrac{m_1\vec{a_1}+m_2\vec{a_2}}{m_1+m_2}

=\dfrac{mg+mg}{m+m}downwards
=gdownwards

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