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The potential energy of a particle of mass 100g moving along x axis is given by U= 5x(x-4) where x is in meters. The period of oscillation is ????

The potential energy of a particle of mass 100g moving along x axis is given by U= 5x(x-4) where x is in meters. The period of oscillation is ????

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Grade:12th pass

2 Answers

Suraj Singh
148 Points
5 years ago
Hy shivaniWe know that negative of potential energy gradient equals to force acting on it... ie F= - dU/dx... Differentiate the above equation them we get F= - 10x +some constant... From here K=10=mw^2.. We get w =10... Therefore period is pi/5 ... Hope U like it
Kushagra Madhukar
askIITians Faculty 629 Points
2 years ago
Dear student,
Please find the attached solution to your problem below.
 
Since, F= – dU/dx
we get F = – 10x + some constant
From here K = 10 = mw^2
We get w = 10
Therefore period of oscillation,T = 2(pi)/w = pi/5
 
Hope it helps.
Thanks and regards,
Kushagra

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