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Grade 12th passAIPMT

The potential energy of a particle of mass 100g moving along x axis is given by U= 5x(x-4) where x is in meters. The period of oscillation is ????

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Shivani

9 Years agoGrade 12th pass

2 Answers

Suraj Singh

9 Years ago

Hy shivaniWe know that negative of potential energy gradient equals to force acting on it... ie F= - dU/dx... Differentiate the above equation them we get F= - 10x +some constant... From here K=10=mw^2.. We get w =10... Therefore period is pi/5 ... Hope U like it

Kushagra Madhukar

6 Years ago

Dear student,

Please find the attached solution to your problem below.

Since, F= – dU/dx

we get F = – 10x + some constant

From here K = 10 = mw^2

We get w = 10

Therefore period of oscillation,T = 2(pi)/w = pi/5

Hope it helps.

Thanks and regards,

Kushagra

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