Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Q.177 DOB Genetics

Q.177 DOB Genetics

Question Image
Grade:12th pass

6 Answers

Raheema Javed
156 Points
6 years ago
The answer is C.
Recombiantion frequency is given to be 20% that is each will produce 10% recombinants that is + a and +b . Parentals appear in majority in a cross hence they will appear 80% times. That means each of the parentals that is ++ and ab will appear 40%

Hence option C.
Sumreet Johar State University of New York,Stony Brook, USA
askIITians Faculty 30 Points
6 years ago
Hi

Dihybrid Cross will be between F1 progeny of above cross. So, F1 progeny of above cross will be ++/ab. Gamestes produced by this individual will be ++, +a, +b and ab. In this cae, +a and +b are recombinant products. These total show recombination frequwency of 20%. So, each will be produced at a frequency of 10%. Non recombinant products ++ and ab will be at a total frequency of 80% indicating at each of these gamestes will be produced at 40% frequency.

So, the answer is (C).
Sumreet Johar State University of New York,Stony Brook, USA
askIITians Faculty 30 Points
6 years ago
Hi

Dihybrid Cross will be between F1 progeny of above cross. So, F1 progeny of above cross will be ++/ab. Gamestes produced by this individual will be ++, +a, +b and ab. In this cae, +a and +b are recombinant products. These total show recombination frequwency of 20%. So, each will be produced at a frequency of 10%. Non recombinant products ++ and ab will be at a total frequency of 80% indicating at each of these gamestes will be produced at 40% frequency.

So, the answer is (C).
Sumreet Johar State University of New York,Stony Brook, USA
askIITians Faculty 30 Points
6 years ago
Hi Student

Dihybrid Cross will be between F1 progeny of above cross. So, F1 progeny of above cross will be ++/ab. Gamestes produced by this individual will be ++, +a, +b and ab. In this cae, +a and +b are recombinant products. These total show recombination frequwency of 20%. So, each will be produced at a frequency of 10%. Non recombinant products ++ and ab will be at a total frequency of 80% indicating at each of these gamestes will be produced at 40% frequency.

So, the answer is (C).
Sumreet Johar State University of New York,Stony Brook, USA
askIITians Faculty 30 Points
6 years ago
Hi Student

Dihybrid Cross will be between F1 progeny of above cross. So, F1 progeny of above cross will be ++/ab. Gamestes produced by this individual will be ++, +a, +b and ab. In this cae, +a and +b are recombinant products. These total show recombination frequwency of 20%. So, each will be produced at a frequency of 10%. Non recombinant products ++ and ab will be at a total frequency of 80% indicating at each of these gamestes will be produced at 40% frequency.

So, the answer is (C).
Sumreet Johar State University of New York,Stony Brook, USA
askIITians Faculty 30 Points
6 years ago
Hi

Dihybrid Cross will be between F1 progeny of above cross. So, F1 progeny of above cross will be ++/ab. Gamestes produced by this individual will be ++, +a, +b and ab. In this cae, +a and +b are recombinant products. These total show recombination frequwency of 20%. So, each will be produced at a frequency of 10%. Non recombinant products ++ and ab will be at a total frequency of 80% indicating at each of these gamestes will be produced at 40% frequency.

So, the answer is (C).

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free