Q.177 DOB Genetics

The answer is C.
Recombiantion frequency is given to be 20% that is each will produce 10% recombinants that is + a and +b . Parentals appear in majority in a cross hence they will appear 80% times. That means each of the parentals that is ++ and ab will appear 40%

Hence option C.

Hi

Dihybrid Cross will be between F1 progeny of above cross. So, F1 progeny of above cross will be ++/ab. Gamestes produced by this individual will be ++, +a, +b and ab. In this cae, +a and +b are recombinant products. These total show recombination frequwency of 20%. So, each will be produced at a frequency of 10%. Non recombinant products ++ and ab will be at a total frequency of 80% indicating at each of these gamestes will be produced at 40% frequency.

So, the answer is (C).

Hi

Dihybrid Cross will be between F1 progeny of above cross. So, F1 progeny of above cross will be ++/ab. Gamestes produced by this individual will be ++, +a, +b and ab. In this cae, +a and +b are recombinant products. These total show recombination frequwency of 20%. So, each will be produced at a frequency of 10%. Non recombinant products ++ and ab will be at a total frequency of 80% indicating at each of these gamestes will be produced at 40% frequency.

So, the answer is (C).

Hi Student

Dihybrid Cross will be between F1 progeny of above cross. So, F1 progeny of above cross will be ++/ab. Gamestes produced by this individual will be ++, +a, +b and ab. In this cae, +a and +b are recombinant products. These total show recombination frequwency of 20%. So, each will be produced at a frequency of 10%. Non recombinant products ++ and ab will be at a total frequency of 80% indicating at each of these gamestes will be produced at 40% frequency.

So, the answer is (C).

Hi Student

Dihybrid Cross will be between F1 progeny of above cross. So, F1 progeny of above cross will be ++/ab. Gamestes produced by this individual will be ++, +a, +b and ab. In this cae, +a and +b are recombinant products. These total show recombination frequwency of 20%. So, each will be produced at a frequency of 10%. Non recombinant products ++ and ab will be at a total frequency of 80% indicating at each of these gamestes will be produced at 40% frequency.

So, the answer is (C).

Hi

Dihybrid Cross will be between F1 progeny of above cross. So, F1 progeny of above cross will be ++/ab. Gamestes produced by this individual will be ++, +a, +b and ab. In this cae, +a and +b are recombinant products. These total show recombination frequwency of 20%. So, each will be produced at a frequency of 10%. Non recombinant products ++ and ab will be at a total frequency of 80% indicating at each of these gamestes will be produced at 40% frequency.

So, the answer is (C).