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Please provide a detailed solution for this question.Pg 414.

Please provide a detailed solution for this question.Pg 414.

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Grade:12th pass

1 Answers

Vikas TU
14149 Points
5 years ago
From the activation energy formulae:
K1 = Ae^(-Ea/300R)
and
K2 = Ae^(-Ea/280R)
Dividing both the eqns. we get,
K1/K2 = e^(-Ea/300R + Ea/280R)
K1/K2 => e^(-11570/300*1.987 + 11570/280*1.987) => e^(5.47) = 237.46

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