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Grade 12th passAIPMT

ph of a solution obtained by mixing 100ml hcl soln of ph 2 and 400ml hcl soln of ph 3

Profile image of Piyush Peeyush
10 Years agoGrade 12th pass
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1 Answer

Profile image of Bejoi Mathew
9 Years ago
To solve this you have to follow this method,
As both solutions are acids you have to use ‘+’ to separate them.
solution A: 100ml and 10-2N
solution B: 400ml and 10-3N
N1V1 + N2V2 = NtVt
100* 10-2 + 400* 10-3 = Nt * 500
Solve for Nt,(i think you will be getting 28 * 10-4)
pH= -log (H+)
pH= – log (28 * 10-4)
PLEASE SOLVE FROM HERE ON.
HOPE YOU GRABBED THE CONCEPT.
BEST OF LUCK!

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