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one of the rectangular components of force of 40N is 20N . find the angle it makes with this component

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2 years ago

```							F(x)=Fcos(alpha) Where alpha is angle between force and that rectangular component So, 20=40cos(alpha) 20/40=cos(alpha) 1/2=cos(alpha) (1/2)cos^-1=alpha alpha=60° I.e. it makes angle of 60° with component
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2 years ago
```							Given:           Resultant force(R) = 40 N           Force in x-axis direction (A) = 20 NTo find:           Angle  between "R" vector and "A" vectorSolution:           A=R cos(x)           20=40 cos(x)           20/40= cos(x)          1/2 = cos(x)            Cos(60)=cos(x)So,       x=60°
```
one year ago
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