On an object of mass 1kg moving along x-axis with constant speed 8m/s a constant force 2N is applied in positive y-direction.Find its speed after 4 seconds.?
Lakshmi Vinod
8 Years agoGrade 12th pass
2 Answers
Debdeep
8 Years ago
Velocity along x=8(constant) Acceleration along y=2m/s^2Velocity along y after 4 s=2*4=8m/sSpeed =8\/2m/s
Deligant
7 Years ago
Mass=1kg. Velocity= 8i^. Force=2j^. F= ma so. 2j^=1.v-u/t. = v-8i^/4. So 8j^+8i^=v. Since he is asking the magnitude. root over 82+82=8root 2