In the arrangement shown in the figure, The ends P and Q of an unstretchable string move downwards with uniform speed “v”. Pulleys A and B are fixed. Mass M moves upwards with a speed?

Question

Sourabh Singh · Answer

The block of mass m is moving up with a speed of 2*v*cos(phi)

Sangram sahoo · Answer

Let the speed of mass M be v .The point on thread just connected to mass M will also have the same velocity .The component of the v along the thread is v cos θ . That means any point on the thread must be moving with speed v cos θ .As it is given that thread is moving with velocity u .That meansv cos θ = u

Kushagra Madhukar · Answer

Dear student, Please find the answer to your question. The block of mass m is moving up with a speed of 2*v*cos( ɸ ) Thanks and regards, Kushagra

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In the arrangement shown in the figure, The ends P and Q of an unstretchable string move downwards with uniform speed “v”. Pulleys A and B are fixed. Mass M moves upwards with a speed?

In the arrangement shown in the figure, The ends P and Q of an unstretchable string move downwards with uniform speed “v”. Pulleys A and B are fixed. Mass M moves upwards with a speed?

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In the arrangement shown in the figure, The ends P and Q of an unstretchable string move downwards with uniform speed “v”. Pulleys A and B are fixed. Mass M moves upwards with a speed?

In the arrangement shown in the figure, The ends P and Q of an unstretchable string move downwards with uniform speed “v”. Pulleys A and B are fixed. Mass M moves upwards with a speed?

3 Answers

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