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In a random mating population frequency of disease causing dominant allele is 70%. What will be frequency of heterozygous individual in population. (1)64% (2)21% (3)42% (4)24% Please solve it well.

In a random mating population frequency of disease causing dominant allele is 70%. What will be frequency of heterozygous individual in population.
(1)64%
(2)21%
(3)42%
(4)24%
Please solve it well.

Grade:

1 Answers

Sruthi I Mohan
61 Points
3 years ago
P=70%=0.7
we knoe that P + Q = 1
so Q=0.3
frequency of heterozygous population=2PQ
                                                     =2*0.7*0.3
                                                     =0.42
                                               in %=42%

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