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In a random mating population frequency of disease causing dominant allele is 70%. What will be frequency of heterozygous individual in population.
(1)64%
(2)21%
(3)42%
(4)24%
Please solve it well.

Profile image of Sayeda Mahfuja Rahman
8 Years agoGrade
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1 Answer

Profile image of Sruthi I Mohan
ApprovedApproved Tutor Answer8 Years ago
P=70%=0.7
we knoe that P + Q = 1
so Q=0.3
frequency of heterozygous population=2PQ
                                                     =2*0.7*0.3
                                                     =0.42
                                               in %=42%

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