Grade 12AIPMT

In a population of 1000
Individual 160 individual are affected with thalassemia which is an autosomal recessive disorder find out homozygous and heterozygous dominant individual in the population

Tejas bhave

7 Years agoGrade 12

7 Years ago

Dear student

Frequency of recessive individual (p²) is 160/1000 = 0.16,

frequency of recessive allele, p is 0.4

Frequency of dominant allele q is 0.6 and frequency of dominant individuals is q² =0.36

Therefore , number of homozygous dominant individuals are 0.36*1000=360

Frequency of heterozygous individual is 2pq = 0.48

Therefore, number of heterozygous dominant individuals are 0.48*1000=480

WITH REGARDS

MAHIMA

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