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Grade: 12
        
In a population of 1000
Individual 160 individual are affected with thalassemia which is an autosomal recessive disorder find out homozygous and heterozygous dominant individual in the population
one year ago

Answers : (1)

Mahima Kanawat
1010 Points
							
Dear student 
Frequency of recessive individual (p2) is 160/1000 = 0.16,
frequency of recessive allele, p is 0.4
Frequency of dominant allele q is 0.6 and frequency of dominant individuals is q2 =0.36
Therefore  , number of homozygous dominant individuals are 0.36*1000=360
Frequency of heterozygous individual is 2pq = 0.48
Therefore, number of heterozygous dominant individuals are 0.48*1000=480
WITH REGARDS 
MAHIMA 
ASKIITIANS FORUM EXPERT 
 
one year ago
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