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If KE of a proton is increased nine times , the wavelenght of the de- broglie wave associated with it would become???

safai , 8 Years ago
Grade 12th pass
anser 1 Answers
Prathamesh Kulkarni

Last Activity: 8 Years ago

Lambda = h/sqrt 2me Therefore lambda1/lambda2 = sqrt E2/E1 .....(1)As it is given that ke becomes nine times Therefore let E1 be initial ke and E2 be final keTherefore E1 = 9E2 Therefore from eqn 1We get....lambda1/lambda2 = sqrt E2/9E2lambda 1/lambda2 = 1/3

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