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Grade: 12th pass
        If KE of a proton is increased nine times , the wavelenght of the de- broglie wave associated with it would become???
one year ago

Answers : (1)

Prathamesh Kulkarni
24 Points
							Lambda = h/sqrt 2me Therefore lambda1/lambda2 = sqrt E2/E1 .....(1)As it is given that ke becomes nine times Therefore let E1 be initial ke and E2 be final keTherefore E1 = 9E2 Therefore from eqn 1We get....lambda1/lambda2 = sqrt E2/9E2lambda 1/lambda2 = 1/3
						
one year ago
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