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How to solve this question? Here the options are given different but acc to dimension analysis, the trignometric values are dimenstionless

Yogiraj , 10 Years ago
Grade 12th pass
anser 1 Answers
Eshan
Dear student,

Here, do not assume x and a to be displacement or acceleration, respectively. Had this been the case, 1(dimensionless) could not be subtracted from the term\dfrac{x}{a}on the right hand side.

All we can know from this term is that the dimensions of x and a are the same. Also, rightly said, the term insidesin^{-1}must be dimensionless. Hence the dimensions of the right hand side is that ofa^n.

The denominator of the integral term has dimensions of that of x or a. The numerator has that ofx^2ora^2, making the overall term have dimensions of x or a.

Since the dimensions of RHS and LHS must be same, the dimensions ofa^nis equal to that of a. Hence n=1.
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