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How many 3 digit no. are such that exactly one of digits is 5

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2 years ago

```							Dear Raj To calculate the 3 digit numbers with exactly one of its digit as 5, we need to use permutation and combination.Consider a 3 digit number ‘ABC’Case 1) A=5, thus B and C can be any digits but 5… so total of 9 digits (0,1,2,3,4,6,7,8,9) can replace B and CTherefore total combinations = 1*9*9 = 81Case 2) B=5, thus C be any digit but 5 while A can be any digit but 0 & 5. A cannot be 0 as it will violate the rule of being a 3 digit number.Thus total combinations = 8*1*9 = 72Case 3) C=5, on similar lines as case 2 thus total combinations = 8*9*1 = 72Therefore total combinations = 81 + 72 + 72 = 225Thus, there are 225 3 digit numbers who have exactly one of its digit as 5 RegardsArun (AskIITians Forum Expert)
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2 years ago
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