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From equilibrium class 11

From equilibrium class 11

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3 Answers

Adarsh
733 Points
6 years ago
For the first question
ΔGo   = -2.303RTlogKC
logKC = ΔGo/-2.303RT
         = -13.8*1000/2.303*8.314*298
         = -2.4186
Taking antilog we get the value of KC as 0.00382.
Please approve if my answer is correct.
Adarsh
733 Points
6 years ago
For the second part of the question
ΔGo   = -2.303RTlogKC
         = -2.303*8.314*log2*1013
         = -254.6767
Adarsh
733 Points
6 years ago
There was a mistake in the solution of the second part of the question
The correct solution is
ΔGo   = -2.303RTlogKC
         = -2.303*8.314*300*log2*1013
         = -76403.01

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