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From equilibrium class 11

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Profile image of Akhila joshi
11 Years agoGrade
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3 Answers

Profile image of Adarsh
11 Years ago
For the first question
ΔGo   = -2.303RTlogKC
logKC = ΔGo/-2.303RT
         = -13.8*1000/2.303*8.314*298
         = -2.4186
Taking antilog we get the value of KC as 0.00382.
Please approve if my answer is correct.
Profile image of Adarsh
11 Years ago
For the second part of the question
ΔGo   = -2.303RTlogKC
         = -2.303*8.314*log2*1013
         = -254.6767
Profile image of Adarsh
11 Years ago
There was a mistake in the solution of the second part of the question
The correct solution is
ΔGo   = -2.303RTlogKC
         = -2.303*8.314*300*log2*1013
         = -76403.01

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