MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
for the real gases in reaction 2Co(g) +O2(g)-2CO2(g) ∆H=-560 kJ.In 10 L rigid vessel at 500K the initial pressure is 70 bar and after the reaction it becomes 50 barr. The change in internal energy is
one year ago

Answers : (2)

Arun
22780 Points
							

We have,             ∆H          =             ∆U          +             ∆(PV)

=             ∆U          +             P2V2 – P1V1 —           —           (1)

As gases deviates from ideal gas behaviour, we cannot use,  ∆H                =             ∆U          +             ∆nRT

Thus                                      ∆(PV)    =             P2V2 – P1V1

=             40×1 – 70×1

=             – 30 L-atm

=             – 3.0 kJ

Therefore, by (1)             – 560     =             ∆U – 3.0

Therefore,                          ∆U          =             – 557 kJ

one year ago
technical gaming artist
23 Points
							
At constant volume ∆H = ∆U + V∆P
 
=> -560 = ∆U + 10 x (-30) x 0.1
=>∆U=-530 kJ
Multipled the value with 0.1 to get answer in Joules
3 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 728 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details