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For intensity I of a light of wavelength 5000 anmgstrom the photoelectron saturation current is 0.40miuA and stopping potential is 1.36v find the work function of the metal

For intensity I of a light of wavelength 5000 anmgstrom the photoelectron saturation current is 0.40miuA and stopping potential is 1.36v find the work function of the metal 

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1 Answers

Eshan
askIITians Faculty 2095 Points
2 years ago
Dear student,

The stopping potential is energy required to stop the electrons emitted with maximum possible kinetic energy,
HenceKE_{max}=1.36eV

The energy of incident photon=\dfrac{hc}{\lambda}=\dfrac{12400}{5000}=2.48eV

Hence from the relationh\nu=W_0+KE_{max}
Work function,W_0=2.48eV-1.36eV=1.12eV

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