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For intensity I of a light of wavelength 5000 anmgstrom the photoelectron saturation current is 0.40miuA and stopping potential is 1.36v find the work function of the metal

Sherba , 8 Years ago

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1 Answers

Eshan

Last Activity: 6 Years ago

Dear student,

The stopping potential is energy required to stop the electrons emitted with maximum possible kinetic energy,
Hence $KE_{max}=1.36eV$

The energy of incident photon= $\dfrac{hc}{\lambda}=\dfrac{12400}{5000}=2.48eV$

Hence from the relation $h\nu=W_0+KE_{max}$
Work function, $W_0=2.48eV-1.36eV=1.12eV$

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