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calculate the diameter of one molecule of an ideal gas having number density 2x10^8cm^-3 and mean free path of molecule 10x^-8cm ( answer is 0.11cm)

 
calculate the diameter of one molecule of an ideal gas having number density 2x10^8cm^-3 and mean free path of molecule 10x^-8cm ( answer is 0.11cm) 

Grade:

1 Answers

Aastha Singh
askIITians Faculty 210 Points
2 years ago
DEAR STUDENT,
APPLY THE FORMULA MEAN FREE PATH, LAMBDA = 1/¶D2NV
WHERE, D- DIAMETER OF MOLECULE
NV= NO. DENSITY OF MOLECULES

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