calculate the diameter of one molecule of an ideal gas having number density 2x10^8cm^-3 and mean free path of molecule 10x^-8cm ( answer is 0.11cm)

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Aastha Singh · Answer

DEAR STUDENT, APPLY THE FORMULA MEAN FREE PATH, LAMBDA = 1/&para;D 2 N V WHERE, D- DIAMETER OF MOLECULE N V = NO. DENSITY OF MOLECULES

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calculate the diameter of one molecule of an ideal gas having number density 2x10^8cm^-3 and mean free path of molecule 10x^-8cm ( answer is 0.11cm)

calculate the diameter of one molecule of an ideal gas having number density 2x10^8cm^-3 and mean free path of molecule 10x^-8cm ( answer is 0.11cm)

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calculate the diameter of one molecule of an ideal gas having number density 2x10^8cm^-3 and mean free path of molecule 10x^-8cm ( answer is 0.11cm)

calculate the diameter of one molecule of an ideal gas having number density 2x10^8cm^-3 and mean free path of molecule 10x^-8cm ( answer is 0.11cm)

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