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At 20g of CaCO3 were put into 10 litre flask and heated to 800 C, 30% of CaCO3 remained unreacted at equilibrium. Kp for decomposition of CaCO3 will be?

Netranjit Borgohain , 9 Years ago
Grade 12
anser 1 Answers
Bhavya

Last Activity: 9 Years ago

CaCO3 ----------> CaO + CO2(g)

0.2 mole 0 0

0.06 0.14 0.14

0.06= 0.2-x therefore x= 0.14

so Kp= p (CO2) only CO2is gas so its pressure is considered

Now,we know PV=nRT thus P=nRT/V

now p = 0.14*0.0821*1073/10
= 1.233

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