An inductor 20 mH, a capacitor 100 microF and a
resistor 50 ohm are connected in series across a
source of emf, V = 10 sin 314 t. The power loss in
the circuit is
(1) 0·79 W
(2) 0·43 W
(3) 1·13 W
(4) 2·74 W

Question

Arun · Answer

Dear student Pav = (Vrms/Z)^2 R Z = 56 ohm hence Pav = (10/56sqrt(2))^2 * 50 = 0.79 Regards Arun (askIITians forum expert)

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An inductor 20 mH, a capacitor 100 microF and a resistor 50 ohm are connected in series across a source of emf, V = 10 sin 314 t. The power loss in the circuit is (1) 0·79 W (2) 0·43 W (3) 1·13 W (4) 2·74 W

An inductor 20 mH, a capacitor 100 microF and a
resistor 50 ohm are connected in series across a
source of emf, V = 10 sin 314 t. The power loss in
the circuit is
(1) 0·79 W
(2) 0·43 W
(3) 1·13 W
(4) 2·74 W

1 Answers

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An inductor 20 mH, a capacitor 100 microF and a resistor 50 ohm are connected in series across a source of emf, V = 10 sin 314 t. The power loss in the circuit is (1) 0·79 W (2) 0·43 W (3) 1·13 W (4) 2·74 W

An inductor 20 mH, a capacitor 100 microF and aresistor 50 ohm are connected in series across asource of emf, V = 10 sin 314 t. The power loss inthe circuit is(1) 0·79 W(2) 0·43 W(3) 1·13 W(4) 2·74 W

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An inductor 20 mH, a capacitor 100 microF and a
resistor 50 ohm are connected in series across a
source of emf, V = 10 sin 314 t. The power loss in
the circuit is
(1) 0·79 W
(2) 0·43 W
(3) 1·13 W
(4) 2·74 W