Pooja
Last Activity: 5 Years ago
We calculate flux in unit time which is magnetic induction
Flux = BA
For loop length is a so A=a2
Resistance of full length is R
As it shaped into square the resistance of each arm would be R/4 so current in each arm would be I/4 the original current
B= 4× field due to one wire at centre
= 4 × u0 I/4 ÷ 4 π a/2 × {2÷(2)1/2}
= I/(2)1/2a
Induction at centre =I/ (2)1/2a × a2
= Ia/(2)1/2
