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Train accelerates with a = 0.2 m/s2 , t = t1and v= v1
v=u + at and v1=0.2t1 or t1= 0.2 v1 /2 …(1)
s=ut+(1/2)at2
Case II:
v2=v1+a2t2(train is retarding and s =s1)
s1=1/2 x 0.2 x t12
v2=v1+a2t2
0 = v1+0.4t2
t2=–v1/0.4 …(2)
s2=v1t2 +(1 /2) x a2t22
t=t1+t2 = 30 min = 1800
t1=1200 secs and t2 = 600 secs
substituting a, v and t in (1) and (3), we get
s1 = 144 km and s2= 72 km
Total distance s= s2+ s2
s = 216km
Regards
Arun (askIITians forum expert)
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