Grade 12th passAIPMT

A thin disc of radius R and mass M has charge q uniformly distributed on it. It rotates with angular velocity w. The ratio of magnetic moment and angular momentum for the disc is(1) q/2M (2) R/2M (3) q^2/2M (4) 2M/q

Aabha Misra

8 Years agoGrade 12th pass

3 Answers

Arun

8 Years ago

Dear student

$\gamma = \mu /L$

= i * $\pi$ * r²/m r² w = (q *w* $\pi$ /2 $\pi$ ) /mw = q/2m

Hence option 1 is correct.

Regards

Arun (askIITians forum expert)

Satyam

7 Years ago

M= q×R^2×w/4 ........1

L= mR^2/2 ...........2

By dividing equation 1 by 2 we will gell,

M/L= q/2m

[M=magnetic moment, w= angular velocity, m= mass, R= rafius, L=angular mementum]

Rishi Sharma

5 Years ago

Dear Student,
Please find below the solution to your problem.

M= q×R^2×w/4 ........1
L= mR^2/2 ...........2
By dividing equation 1 by 2 we will gell,
M/L= q/2m
[M=magnetic moment, w= angular velocity, m= mass, R= rafius, L=angular mementum]

Thanks and Regards