A schematic plot of ln Keq versus inverse of temperature for a reaction is shown below. The reaction must be Options: (a) highly spontaneous at ordinary temperature (b) one with negligible enthalpy change (c) endothermic (d) exothermic

Question

A schematic plot of ln Keq versus inverse of temperature for a reaction is shown below. The reaction must be Options: (a) highly spontaneous at ordinary temperature (b) one with negligible enthalpy change (c) endothermic (d) exothermic

Arun · Answer

Dear student if we find delta H, we find ot negative. hence reaction is exothermic. Hope it helps Regards Arun

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A schematic plot of ln Keq versus inverse of temperature for a reaction is shown below. The reaction must be Options: (a) highly spontaneous at ordinary temperature (b) one with negligible enthalpy change (c) endothermic (d) exothermic

A schematic plot of ln Keq versus inverse of temperature for a reaction is shown below. The reaction must be Options: (a) highly spontaneous at ordinary temperature (b) one with negligible enthalpy change (c) endothermic (d) exothermic

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A schematic plot of ln Keq versus inverse of temperature for a reaction is shown below. The reaction must be Options: (a) highly spontaneous at ordinary temperature (b) one with negligible enthalpy change (c) endothermic (d) exothermic

A schematic plot of ln Keq versus inverse of temperature for a reaction is shown below. The reaction must be Options: (a) highly spontaneous at ordinary temperature (b) one with negligible enthalpy change (c) endothermic (d) exothermic

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