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A roket starts from rest and accelerates with 2g.after height h engine is stopped.what is total height reached [ ans:3h]
Dear student Please attach the image. As the language of question is ambiguous. Hope you understand Thanks and regards
Dear student Accln= 19.6 m/s time t =5secHmax = u square /2gfor initial velocity.a=u/t i.e. 19.6=u/5:. u=19.6×5=98m/s:. Hmax=98 square/2(10)9604/20=480.2m
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