A roket starts from rest and accelerates with 2g.after height h engine is stopped.what is total height reached [ ans:3h]

Question

Arun · Answer

Dear student Please attach the image. As the language of question is ambiguous. Hope you understand Thanks and regards

Vikas TU · Answer

Dear student Accln= 19.6 m/s time t =5sec Hmax = u square /2g for initial velocity. a=u/t i.e. 19.6=u/5 :. u=19.6×5=98m/s :. Hmax=98 square/2(10) 9604/20=480.2m

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A roket starts from rest and accelerates with 2g.after height h engine is stopped.what is total height reached [ ans:3h]

A roket starts from rest and accelerates with 2g.after height h engine is stopped.what is total height reached [ ans:3h]

A roket starts from rest and accelerates with 2g.after height h engine is stopped.what is total height reached [ ans:3h]

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