A projectile can have the same range for two angles of projection .If t1 and t2 be the Times of flight in two cases then initial velocity of projectile is

Question

Harshit Singh · Answer

Dear Student Range is same R =u 1 2 sin2&theta;​ 1 /g =u 2 2 sin2&theta;​ 2 /g Since , The angle of projection is different t1 / t2 = u 1 sin&theta;​ 1 / u 2 sin&theta;​ 2 from these equations , you can calculate the required values Thanks

Yashraj · Answer

Practice previous year questions many times.. Appear for a test series and analyse it properly (Giving 2–3 hours) Revise your notes multiple times till they enter your soul :) Find your strong points and chapters, work on them.. Solve other people’s doubts. It makes your own concepts very clear

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A projectile can have the same range for two angles of projection .If t1 and t2 be the Times of flight in two cases then initial velocity of projectile is

A projectile can have the same range for two angles of projection .If t1 and t2 be the Times of flight in two cases then initial velocity of projectile is

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