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A particle is projected horizontally from the top of a tower with velocity 10 m/s. The radius of curvature of the path of the particle after 1 s is

Mayank Jain , 7 Years ago
Grade 12th pass
anser 1 Answers
Arun

Last Activity: 7 Years ago

 
v2/perpendicular acceleration is the formula for radius of carvature. 
v=10m/s in horizontal always.
v in vertical is 1*10= 10 m/s
so speed=10 root2 m/s
so r=(10 root2)2/10=20 m

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