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A particle is projected horizontally from the top of a tower with velocity 10 m/s. The radius of curvature of the path of the particle after 1 s is

A particle is projected horizontally from the top of a tower with velocity 10 m/s. The radius of curvature of the path of the particle after 1 s is

Grade:12th pass

1 Answers

Arun
25757 Points
5 years ago
 
v2/perpendicular acceleration is the formula for radius of carvature. 
v=10m/s in horizontal always.
v in vertical is 1*10= 10 m/s
so speed=10 root2 m/s
so r=(10 root2)2/10=20 m

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