A particle is projected horizontally from the top of a tower with velocity 10 m/s. The radius of curvature of the path of the particle after 1 s is

Question

Arun · Answer

v 2 /perpendicular acceleration is the formula for radius of carvature. v=10m/s in horizontal always. v in vertical is 1*10= 10 m/s so speed=10 root2 m/s so r=(10 root2) 2 /10=20 m

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A particle is projected horizontally from the top of a tower with velocity 10 m/s. The radius of curvature of the path of the particle after 1 s is

A particle is projected horizontally from the top of a tower with velocity 10 m/s. The radius of curvature of the path of the particle after 1 s is

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A particle is projected horizontally from the top of a tower with velocity 10 m/s. The radius of curvature of the path of the particle after 1 s is

A particle is projected horizontally from the top of a tower with velocity 10 m/s. The radius of curvature of the path of the particle after 1 s is

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