A PARTICLE IS PROJECTED AT AN ANGLE 30 degree FROM HORIZONTAL IN A VERTICAL PLANE . ITS CENTRIPETAL ACCELERATION AT HIGHEST POINT OF ITS MOTION IS WHAT?

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Arnab · Answer

First of all you have to calculate the radius of curvature of the projectile. And it will be u2cos2theta/g.At the highest position the particle gains a velocity v cos theta. So the answer will be u2cos2theta/r.o.c.That is g

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A PARTICLE IS PROJECTED AT AN ANGLE 30 degree FROM HORIZONTAL IN A VERTICAL PLANE . ITS CENTRIPETAL ACCELERATION AT HIGHEST POINT OF ITS MOTION IS WHAT?

A PARTICLE IS PROJECTED AT AN ANGLE 30 degree FROM HORIZONTAL IN A VERTICAL PLANE . ITS CENTRIPETAL ACCELERATION AT HIGHEST POINT OF ITS MOTION IS WHAT?

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A PARTICLE IS PROJECTED AT AN ANGLE 30 degree FROM HORIZONTAL IN A VERTICAL PLANE . ITS CENTRIPETAL ACCELERATION AT HIGHEST POINT OF ITS MOTION IS WHAT?

A PARTICLE IS PROJECTED AT AN ANGLE 30 degree FROM HORIZONTAL IN A VERTICAL PLANE . ITS CENTRIPETAL ACCELERATION AT HIGHEST POINT OF ITS MOTION IS WHAT?

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