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A diatomic gas of molecular mass 40g/mol is filled in a container at temperature 30°c. It is moving with velocity 200 m/s. If it is suddenly stop,the rise of the temperature of the gas is

Eshan
3 years ago
Dear student,

From conservation of energy, work done on gas= Change in internal energy of the system

Hence$\dpi{80} \dfrac{1}{2}mv^2=nC_V\Delta T=\dfrac{m}{M_0}C_V\Delta T$

$\dpi{80} \implies \Delta T=\dfrac{M_0v^2}{2C_V}=\dfrac{0.04\times 200^2}{2\dfrac{5}{2}R}$$\dpi{80} \implies \Delta T=\dfrac{M_0v^2}{2C_V}=\dfrac{0.04\times 200^2}{2(\dfrac{5}{2}R)}=\dfrac{320}{R}^{\circ}$
Rishi Sharma