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A body starts from rest and uniformly accelerated for 10 seconds so that its velocity becomes 100m/s. It then maintains the speed for 10 more seconds. The distance travelled in first 10 seconds to next 10 seconds will be in the ratioa) 1:1b) 1:2c) 1:3d) 1:4

Jobin C J , 6 Years ago
Grade 12th pass
anser 1 Answers
Eshan

Last Activity: 6 Years ago

Dear student,

For the first 10 seconds,v=u+at\implies a=\dfrac{100m/s}{10s}=10m/s^2
Hence distance travelled in the time=s_1=\dfrac{1}{2}at^2=500m

For the next 10 seconds, distance travelleds_2=vt=100m/s \times 10s=1000m
Therefores_1:s_2=1:2

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