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A body starts from rest and uniformly accelerated for 10 seconds so that its velocity becomes 100m/s. It then maintains the speed for 10 more seconds. The distance travelled in first 10 seconds to next 10 seconds will be in the ratio
a) 1:1
b) 1:2
c) 1:3
d) 1:4

Jobin C J , 7 Years ago

Grade 12th pass

1 Answers

Eshan

Dear student,

For the first 10 seconds, $v=u+at\implies a=\dfrac{100m/s}{10s}=10m/s^2$
Hence distance travelled in the time= $s_1=\dfrac{1}{2}at^2=500m$

For the next 10 seconds, distance travelled $s_2=vt=100m/s \times 10s=1000m$
Therefore $s_1:s_2=1:2$

Approved

Last Activity: 7 Years ago

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