# A body starts from rest and uniformly accelerated for 10 seconds so that its velocity becomes 100m/s. It then maintains the speed for 10 more seconds. The distance travelled in first 10 seconds to next 10 seconds will be in the ratioa) 1:1b) 1:2c) 1:3d) 1:4

Eshan
askIITians Faculty 2095 Points
4 years ago
Dear student,

For the first 10 seconds,$\dpi{80} v=u+at\implies a=\dfrac{100m/s}{10s}=10m/s^2$
Hence distance travelled in the time=$\dpi{80} s_1=\dfrac{1}{2}at^2=500m$

For the next 10 seconds, distance travelled$\dpi{80} s_2=vt=100m/s \times 10s=1000m$
Therefore$\dpi{80} s_1:s_2=1:2$