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A body released from the top of tower of height H. it takes t time to reach the ground where is the body t/2 time after release Find the hight at t/2

A body released from the top of tower of height H. it takes t time to reach the ground where is the body t/2 time after release Find the hight at t/2

Question Image
Grade:11

1 Answers

Arun
25763 Points
3 years ago
Dear Ekta
 
 

the acceleration of the ball will be g. Initial velocity will be 0. 

 

in T sec. body travels h mts.  

 

 by applying equations of motion we get

 

                                         s= ut +1/2gT2

 

                                         h = 1/2gT2                                          ------[1]

 

in T/2 sec                      h= 1/2gT2/4                                     -------[2]

 

from [1] and [2] we get h=h/4 distance from point of release.

 

therefore distance from ground is h-h/4 =3h/4

 

Regards

Arun (askIITians forum expert)

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