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A block of mass m kg is kept on a weighing machine in an elevator. If the elevator is retarding upward by a m/s², the reading of weighing machine is(1) mg(2) m(g-a)(3) m(1-a/g)(4) m(g+a)
Dear student,Elevator retarding upwards means that it is accelerating downwards with magnitude ‘a’. Hence block experience pseudo force ma upwards. Hence the reading of wieghing machine= m(g-a)
As lift goes upward net acc. is g+aBut here a is retarding so -a should be taken so it will be g-aHence, N=m(g-a) In kgf the weighing machine reading= m(1-a/g)
The normal force tge acts on the blocl is m{g-a}Therefore the weight shown will be m{g-a} please upvote
here is ur solution for the question . kindly do upvte . this is just formula based and a easy problem
Since it is moving upward , thereforeN-mg=ma N= m(g+a)And weighing machine measures Normal reaction not weight if a person . It measures weight in non inertial frame of reference where a = 0 .So option no 4 is correct .Thank you 😊
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