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A block is kept on a smooth inclined plane of angle of inclinaton 30 degree that moves with a constant acceleration so that the block does not slide relative to the inclined plane .Let F 1 be the contact force between the block and the plane .Now the inclined plane stops and let F 2 be the contact force between the two in this case .Then F 1 /F 2 IS (a) 1 (b)4/3 (c)2 (d)3/2
in the first case,F1 sin = 30=maand F1 cos=30=mg or f1 = mg/cos30 and in the second case,f2 =mg cos 30 therefore,F2 = mg cos 30F1/F2 =1/cos^2 30 = 4/3
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