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AIPMT> A balloon of gross weight W newton is des...

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A balloon of gross weight W newton is descending down with an acceleration of f unit. The weight that must be removed or dropped down so as to give the balloon an equal upward acceleration.

Wf/g

2Wf/g

2Wf/g+f

W(g+f)/f
The problem I face is formation of the equations.

Norman Manchu , 7 Years ago

Grade 10

1 Answers

Eshan

Last Activity: 7 Years ago

Dear student,

The mass of the balloon, if its weight is W is [m=\dfrac{W}{g}]

The bouyant force [B] acting the body is same independent of the direction of movement of balloon. Hence while moving down,

$W-B=mf$

While moving up,

$B-W'=mf$

Hence the weight that must be removed= $W-W'=2mf=2\dfrac{W}{g}f$

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