A ball is thrown from ground with speed up at an angle theta with the horizontal, at the same instant from the same position a boy runs along the ground with speed 1.732u/2 to catch the ball .If the boy is able to catch the ball, the angle of projection theta is

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Arun · Answer

Man will catch the ball if the horizontal component of velocity becomes equal to the constant speed of man i.e. θ=30 0

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A ball is thrown from ground with speed up at an angle theta with the horizontal, at the same instant from the same position a boy runs along the ground with speed 1.732u/2 to catch the ball .If the boy is able to catch the ball, the angle of projection theta is

A ball is thrown from ground with speed up at an angle theta with the horizontal, at the same instant from the same position a boy runs along the ground with speed 1.732u/2 to catch the ball .If the boy is able to catch the ball, the angle of projection theta is

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A ball is thrown from ground with speed up at an angle theta with the horizontal, at the same instant from the same position a boy runs along the ground with speed 1.732u/2 to catch the ball .If the boy is able to catch the ball, the angle of projection theta is

A ball is thrown from ground with speed up at an angle theta with the horizontal, at the same instant from the same position a boy runs along the ground with speed 1.732u/2 to catch the ball .If the boy is able to catch the ball, the angle of projection theta is

1 Answers

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