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A ball attached to one end of a string swings in a vertical plane such that its acceleration at point A (extreme position) is equal to its acceleration at point B (mean position). The angle theta is

yashra singh , 5 Years ago
Grade 12th pass
anser 1 Answers
Vikas TU

Last Activity: 5 Years ago

Hiii Yashra
v^2/l = gsin(a)
where a is the maximum deflection from newtons law in projection form.
-mgsinQ = mv dv/ldQ
v^2 = 2glsonQdQ = 2gl(1-cosQ)
solving equations 
2gl (1-cosa) = lgcosa
cos(a) = 2/3 
a = 53 degree.
 

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