Flag AIPMT> 1.the amount of charge possessed by 1kg o...
question mark

1.the amount of charge possessed by 1kg of electrons?2.A partice os mass m and carrying charge -q1 is moving around a charge +q2 along a circular path of radius r.find period of revolution of the charge -q1.3.The electric field at 2R from the centre of a uniformly charged non-conducting sphere of radius R is E.The electric field at a distance of R/2 from the centre will be?(the answer was given as 2E..but i’ve studied that the electric field at a point inside a uniformly charged sphere is 0?)

Sharon , 9 Years ago
Grade
anser 2 Answers
Abhishek Kumar

Last Activity: 9 Years ago

\therefore1
1e has charge of 1.602 X 10-19 C
So, 9.109 X 10-31 kg has 1.602 X 10-19 C
So, 1 Kg has = 1.602 X 10-19/(9.109 X 10-31) C

2
Kq1q2/r2 = mv2/r Here we need one more equation as there are two variables and only one equation. Or, assumne mvr= nh/2\pi and then solve.
T= 2\pir/v

3
Electric field inside a uniformly charged dielectric sphere is NOT zero. It is zero inside a metallic sphere or any metal.
Electric field inside a uniformly charged dielectric sphere is = kqr/R3

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,
Please find the attached answer to your problem.
 
1
1e has charge of 1.602 X 10-19 C
So, 9.109 X 10-31 kg has 1.602 X 10-19 C
So, 1 Kg has = 1.602 X 10-19/(9.109 X 10-31) C
2
Kq1q2/r2 = mv2/r Here we need one more equation as there are two variables and only one equation. Or, assumne mvr=
nh/2π and then solve.
T = 2πr/v
3
Electric field inside a uniformly charged dielectric sphere is NOT zero. It is zero inside a metallic sphere or any metal. Electric field inside a uniformly charged dielectric sphere is = kqr/R3
 
Hope it helps.
Thanks and regards,
Kushagra

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...