AIPMT> 1.the amount of charge possessed by 1kg o...

1.the amount of charge possessed by 1kg of electrons?2.A partice os mass m and carrying charge -q1 is moving around a charge +q2 along a circular path of radius r.find period of revolution of the charge -q1.3.The electric field at 2R from the centre of a uniformly charged non-conducting sphere of radius R is E.The electric field at a distance of R/2 from the centre will be?(the answer was given as 2E..but i’ve studied that the electric field at a point inside a uniformly charged sphere is 0?)

Sharon , 10 Years ago

Grade

2 Answers

Abhishek Kumar

Last Activity: 10 Years ago

$\therefore$ 1
1e has charge of 1.602 X 10^-19 C
So, 9.109 X 10^-31kg has 1.602 X 10^-19 C
So, 1 Kg has = 1.602 X 10^-19/(9.109 X 10^-31) C

2
Kq₁q₂/r²= mv²/r Here we need one more equation as there are two variables and only one equation. Or, assumne mvr= nh/2 $\pi$ and then solve.
T= 2 $\pi$ r/v

3
Electric field inside a uniformly charged dielectric sphere is NOT zero. It is zero inside a metallic sphere or any metal.
Electric field inside a uniformly charged dielectric sphere is = kqr/R³

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,

Please find the attached answer to your problem.

1e has charge of 1.602 X 10^-19 C

So, 9.109 X 10^-31kg has 1.602 X 10^-19 C

So, 1 Kg has = 1.602 X 10^-19/(9.109 X 10^-31) C

Kq₁q₂/r²= mv²/r Here we need one more equation as there are two variables and only one equation. Or, assumne mvr=

nh/2π and then solve.

T = 2πr/v

Electric field inside a uniformly charged dielectric sphere is NOT zero. It is zero inside a metallic sphere or any metal. Electric field inside a uniformly charged dielectric sphere is = kqr/R³

Hope it helps.

Thanks and regards,

Kushagra