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Urgent!!! Please help with these two questions of Electrochemistry. I need detailed solutions!!!

Abhishek Dogra , 6 Years ago
Grade 11
anser 1 Answers
Aman

Last Activity: 5 Years ago

The solution of second question given below
  AgNO3 --- Ag+   +.   NO3-   according to this equation . One Faraday deposit one mole of electron that's why 3 Faraday deposit 3 mole of electron
For CuSO4 ----- Cu2+   +.  SO4-. Copper required 2 Faraday to deposit one mole of electron that's why 3 Faraday deposit 1.5 mole of electron 
For Al(NO3)---- Al3+.  +.  3NO3-. 3 Faraday deposit one mole of electron
For NaCl ------ Na+. +.   Cl-. 1 Faraday deposit one mole of electron that's why 3 Faraday deposit 3 mole of electron.          
So ratio should be 3:1.5:1:3  after converting in
whole number ratio should 6:3:2:6
 

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