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Urgent!!! Please help with these two questions of Electrochemistry. I need detailed solutions!!!

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Abhishek Dogra

7 Years agoGrade 11

1 Answer

Aman

Approved Tutor Answer7 Years ago

The solution of second question given below

AgNO3 --- Ag+ +. NO3- according to this equation . One Faraday deposit one mole of electron that's why 3 Faraday deposit 3 mole of electron

For CuSO4 ----- Cu2+ +. SO4-. Copper required 2 Faraday to deposit one mole of electron that's why 3 Faraday deposit 1.5 mole of electron

For Al(NO3)---- Al3+. +. 3NO3-. 3 Faraday deposit one mole of electron

For NaCl ------ Na+. +. Cl-. 1 Faraday deposit one mole of electron that's why 3 Faraday deposit 3 mole of electron.

So ratio should be 3:1.5:1:3 after converting in

whole number ratio should 6:3:2:6

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