Arun
Last Activity: 5 Years ago
Dear Abhishek
Let the total angle twisted by A and B is (not mentioned in question) and twist angle made by A and B will be θ1 and θ2 respectively.hence θ=θ1+θ2.......1> (total angle twisted is contribution of individual angular twist)now the force applied produce the torque on B and a restoring torque is produce in A to counter torque of B this continuous till both the rods does not archives the condition of equilibrium.using the formula of torque in both cylinder A and B Torque clockwose by B = torque anticlockwise by A
n* pi* (2r)4 theta2/ 2L = n * pi* (r)4 theta1/ 2L
Theta1 = 16 * theta2
Hence
Theta2 + 16 theta2 = theta
Theta2 = theta/17
And
Theta1 = 16 theta/17